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TOPIC :MAGNETIC EFFECT OF CURRENT

Number of questions are 347, Select_Question:

Number of questions are 347, Select_Question:

Q1) An ideal transformer has primary power of 10kW. The secondary current when the transformer is on load is 25A. If the primary and secondary turns are in ratio is 8:1 then the potential difference applied in the primary coil is ...[ AFMC 1998]

SOLUTION

For ideal transformer power in primary coil=power in secondary coil

V1×I1=V2×I2

10000=V2×25

V2=10000 / 25

Now V1 / V2=n1×n2

V1=V2( n1 / n2

Answer: (c)