TOPIC :MAGNETIC EFFECT OF CURRENT
Number of questions are 347, Select_Question:

QUESTION
Q1) An ideal transformer has primary power of 10kW. The secondary current when the transformer is on load is 25A. If the primary and secondary turns are in ratio is 8:1 then the potential difference applied in the primary coil is ...[ AFMC 1998]




SOLUTION

For ideal transformer power in primary coil=power in secondary coil
V1×I1=V2×I2
10000=V2×25
V2=10000 / 25
Now V1 / V2=n1×n2
V1=V2( n1 / n2
opt4
Answer: (c)