Question
Q144) Mole fraction of solvent in aqueous solution of NaOH having molality of 3 is
SOLUTION
Molality = moles per Kg of solvent
Given 3 moles of NaOH and solvent is water (aqueous)= 1Kg= 55.5
Thus mole faction x
x=55.5/(3+55.5)=0.9487
Answer: (d)