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TOPIC :ELECTROSTATICS

Number of questions are 551, Select_Question:

Number of questions are 551, Select_Question:

Q1) A particle of mass m and charge q is placed at rest in a uniform electric field E and then released. The kinetic energy attend by the particle after moving a distance y is [AFMC 1997]

SOLUTION

Initially charged particle was at rest Initial kinetic energy Ki=0

After releasing charge particle , it attends velocity

Final Kinetic=Kf > 0

Therefore kinetic energy is changed

Now According to work energy theorem ∆K=W

Therefore Kf – Ki=Force x displacement

Ki – 0=F x y displacement is y given

=Eqy ( Force on the charge in electric field E=Eq

Answer is (b)